FizzBuzz
Fizz buzz is a group word game for children to teach them about division. Players take turns to count incrementally, replacing any number divisible by three with the word “fizz”, and any number divisible by five with the word “buzz”.
The game rules
Players generally sit in a circle. The player designated to go first says the number “1”, and the players then count upwards in turn. However, any number divisible by three is replaced by the word fizz, and any number divisible by five by the word buzz. Numbers divisible by 15 become fizz buzz. A player who hesitates or makes a mistake is eliminated from the game.
For example, a typical round of fizz buzz would start as follows:
1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14, Fizz Buzz, 16, 17, Fizz, 19, Buzz, Fizz, 22, 23, Fizz, Buzz, 26, Fizz, 28, 29, Fizz Buzz, 31, 32, Fizz, 34, Buzz, Fizz, …
In Programming
Fizz buzz (often spelled FizzBuzz in this context) has been used as an interview screening device for computer programmers. Writing a program to output the first 100 FizzBuzz numbers is a relatively trivial problem requiring little more than a loop and conditional statements. However, its value in coding interviews is to analyze fundamental coding habits that may be indicative of overall coding ingenuity.
Let's resolve this algorithm challenge using javascript:
in the first line of code, I will be creating the variable N which will resemble the input for the program and its value will be 100 then I will create my function.
n = 100fizbuzz = (n)=> {}
After we have this function created I need to create a for-loop that will count from 1 to the value of N.
n = 100fizbuzz = (n)=> { for (let i = 0; i < n + 1; i++) { }}
Inside the for-loop, I will create a series of conditional statements. The first if-statement checks to see if the number is divisible by 15. and then another 2 conditionals to check if the number is divided by 3 and by 5. The last conditional will print the actual value of N if the number is not divided by 15, 5, or 3.
n = 100
fizbuzz = (n)=> {for (let i = 0; i < n + 1; i++) {
if (i % 15 == 0) console.log("FizzBuzz");
else if (i % 3 == 0) console.log("Fizz");
else if (i % 5 == 0) console.log("Buzz");
else console.log(i); }}
This is the final code;
const n = 100fizbuzz = (n)=> {
for (let i = 0; i < n + 1; i++) {
if (i % 15 == 0) console.log("FizzBuzz");
else if (i % 3 == 0) console.log("Fizz");
else if (i % 5 == 0) console.log("Buzz");
else console.log(i);
}
}fizbuzz(n)
and this will print out the following:
FizzBuzz
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
FizzBuzz
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
FizzBuzz
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
BuzzIt is long but you get the idea. Thank you for your time and I will see you in the next challenge.